Optimal. Leaf size=123 \[ -a^2 \text {Li}_2\left (\frac {2}{a x+1}-1\right )+\frac {a^2 \tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+a^2 \tanh ^{-1}(a x)^2+\frac {1}{4} a^2 \tanh ^{-1}(a x)+2 a^2 \log \left (2-\frac {2}{a x+1}\right ) \tanh ^{-1}(a x)-\frac {a^3 x}{4 \left (1-a^2 x^2\right )}-\frac {\tanh ^{-1}(a x)}{2 x^2}-\frac {a}{2 x} \]
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Rubi [A] time = 0.36, antiderivative size = 123, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 10, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6030, 5982, 5916, 325, 206, 5988, 5932, 2447, 5994, 199} \[ -a^2 \text {PolyLog}\left (2,\frac {2}{a x+1}-1\right )-\frac {a^3 x}{4 \left (1-a^2 x^2\right )}+\frac {a^2 \tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+a^2 \tanh ^{-1}(a x)^2+\frac {1}{4} a^2 \tanh ^{-1}(a x)+2 a^2 \log \left (2-\frac {2}{a x+1}\right ) \tanh ^{-1}(a x)-\frac {\tanh ^{-1}(a x)}{2 x^2}-\frac {a}{2 x} \]
Antiderivative was successfully verified.
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Rule 199
Rule 206
Rule 325
Rule 2447
Rule 5916
Rule 5932
Rule 5982
Rule 5988
Rule 5994
Rule 6030
Rubi steps
\begin {align*} \int \frac {\tanh ^{-1}(a x)}{x^3 \left (1-a^2 x^2\right )^2} \, dx &=a^2 \int \frac {\tanh ^{-1}(a x)}{x \left (1-a^2 x^2\right )^2} \, dx+\int \frac {\tanh ^{-1}(a x)}{x^3 \left (1-a^2 x^2\right )} \, dx\\ &=2 \left (a^2 \int \frac {\tanh ^{-1}(a x)}{x \left (1-a^2 x^2\right )} \, dx\right )+a^4 \int \frac {x \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac {\tanh ^{-1}(a x)}{x^3} \, dx\\ &=-\frac {\tanh ^{-1}(a x)}{2 x^2}+\frac {a^2 \tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+\frac {1}{2} a \int \frac {1}{x^2 \left (1-a^2 x^2\right )} \, dx+2 \left (\frac {1}{2} a^2 \tanh ^{-1}(a x)^2+a^2 \int \frac {\tanh ^{-1}(a x)}{x (1+a x)} \, dx\right )-\frac {1}{2} a^3 \int \frac {1}{\left (1-a^2 x^2\right )^2} \, dx\\ &=-\frac {a}{2 x}-\frac {a^3 x}{4 \left (1-a^2 x^2\right )}-\frac {\tanh ^{-1}(a x)}{2 x^2}+\frac {a^2 \tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}-\frac {1}{4} a^3 \int \frac {1}{1-a^2 x^2} \, dx+\frac {1}{2} a^3 \int \frac {1}{1-a^2 x^2} \, dx+2 \left (\frac {1}{2} a^2 \tanh ^{-1}(a x)^2+a^2 \tanh ^{-1}(a x) \log \left (2-\frac {2}{1+a x}\right )-a^3 \int \frac {\log \left (2-\frac {2}{1+a x}\right )}{1-a^2 x^2} \, dx\right )\\ &=-\frac {a}{2 x}-\frac {a^3 x}{4 \left (1-a^2 x^2\right )}+\frac {1}{4} a^2 \tanh ^{-1}(a x)-\frac {\tanh ^{-1}(a x)}{2 x^2}+\frac {a^2 \tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+2 \left (\frac {1}{2} a^2 \tanh ^{-1}(a x)^2+a^2 \tanh ^{-1}(a x) \log \left (2-\frac {2}{1+a x}\right )-\frac {1}{2} a^2 \text {Li}_2\left (-1+\frac {2}{1+a x}\right )\right )\\ \end {align*}
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Mathematica [A] time = 0.40, size = 83, normalized size = 0.67 \[ \frac {1}{8} a^2 \left (2 \tanh ^{-1}(a x) \left (-\frac {2}{a^2 x^2}+8 \log \left (1-e^{-2 \tanh ^{-1}(a x)}\right )+\cosh \left (2 \tanh ^{-1}(a x)\right )+2\right )-8 \text {Li}_2\left (e^{-2 \tanh ^{-1}(a x)}\right )-\frac {4}{a x}+8 \tanh ^{-1}(a x)^2-\sinh \left (2 \tanh ^{-1}(a x)\right )\right ) \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.61, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\operatorname {artanh}\left (a x\right )}{a^{4} x^{7} - 2 \, a^{2} x^{5} + x^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {artanh}\left (a x\right )}{{\left (a^{2} x^{2} - 1\right )}^{2} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.07, size = 265, normalized size = 2.15 \[ -\frac {\arctanh \left (a x \right )}{2 x^{2}}+2 a^{2} \arctanh \left (a x \right ) \ln \left (a x \right )-\frac {a^{2} \arctanh \left (a x \right )}{4 \left (a x -1\right )}-a^{2} \arctanh \left (a x \right ) \ln \left (a x -1\right )+\frac {a^{2} \arctanh \left (a x \right )}{4 a x +4}-a^{2} \arctanh \left (a x \right ) \ln \left (a x +1\right )-a^{2} \dilog \left (a x \right )-a^{2} \dilog \left (a x +1\right )-a^{2} \ln \left (a x \right ) \ln \left (a x +1\right )-\frac {a^{2} \ln \left (a x -1\right )^{2}}{4}+a^{2} \dilog \left (\frac {1}{2}+\frac {a x}{2}\right )+\frac {a^{2} \ln \left (a x -1\right ) \ln \left (\frac {1}{2}+\frac {a x}{2}\right )}{2}+\frac {a^{2} \ln \left (a x +1\right )^{2}}{4}+\frac {a^{2} \ln \left (-\frac {a x}{2}+\frac {1}{2}\right ) \ln \left (\frac {1}{2}+\frac {a x}{2}\right )}{2}-\frac {a^{2} \ln \left (-\frac {a x}{2}+\frac {1}{2}\right ) \ln \left (a x +1\right )}{2}-\frac {a}{2 x}+\frac {a^{2}}{8 a x -8}-\frac {a^{2} \ln \left (a x -1\right )}{8}+\frac {a^{2}}{8 a x +8}+\frac {a^{2} \ln \left (a x +1\right )}{8} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.33, size = 233, normalized size = 1.89 \[ \frac {1}{8} \, {\left (8 \, {\left (\log \left (a x - 1\right ) \log \left (\frac {1}{2} \, a x + \frac {1}{2}\right ) + {\rm Li}_2\left (-\frac {1}{2} \, a x + \frac {1}{2}\right )\right )} a - 8 \, {\left (\log \left (a x + 1\right ) \log \relax (x) + {\rm Li}_2\left (-a x\right )\right )} a + 8 \, {\left (\log \left (-a x + 1\right ) \log \relax (x) + {\rm Li}_2\left (a x\right )\right )} a + a \log \left (a x + 1\right ) - a \log \left (a x - 1\right ) - \frac {2 \, {\left (a^{2} x^{2} - {\left (a^{3} x^{3} - a x\right )} \log \left (a x + 1\right )^{2} + 2 \, {\left (a^{3} x^{3} - a x\right )} \log \left (a x + 1\right ) \log \left (a x - 1\right ) + {\left (a^{3} x^{3} - a x\right )} \log \left (a x - 1\right )^{2} - 2\right )}}{a^{2} x^{3} - x}\right )} a - \frac {1}{2} \, {\left (2 \, a^{2} \log \left (a^{2} x^{2} - 1\right ) - 2 \, a^{2} \log \left (x^{2}\right ) + \frac {2 \, a^{2} x^{2} - 1}{a^{2} x^{4} - x^{2}}\right )} \operatorname {artanh}\left (a x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\mathrm {atanh}\left (a\,x\right )}{x^3\,{\left (a^2\,x^2-1\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {atanh}{\left (a x \right )}}{x^{3} \left (a x - 1\right )^{2} \left (a x + 1\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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